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university-solution-explainer大学解决方案解释者

Agent Skill

university-solution-explainer 用于查找、检索和筛选相关信息,适合在 OpenClaw 中需要根据关键词、任务场景或来源线索快速定位候选结果时使用。可结合来源仓库、安装命令和原始 README 继续核验具体用法。安装前建议确认权限范围、维护状态,以及是否会触发联网、命令执行或文件读写。

总安装

6,007

周安装

243

GitHub Stars

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下载量

1,886
OpenClaw

安装说明

本站只整理中文说明和来源信息,不托管安装包,也不代用户安装。

GitHub

来源数

2

许可证

MIT-0

最后核验

2026-05-01

来源状态

来源可访问

安装方式

通过对话安装

复制提示词发给支持本地命令或 Skills 的 AI 助手,先确认命令和权限,再让它执行。

请帮我安装这个 Agent Skill:university-solution-explainer(大学解决方案解释者)
来源仓库:https://github.com/eloklam/university-solution-explainer
安装命令:
openclaw skills install university-solution-explainer
安装前请先检查当前环境是否支持对应 CLI,并向我确认将要执行的命令、安装目录、联网范围和文件读写权限;确认后再执行。

命令行安装

复制命令到本机终端执行。该命令会通过 OpenClaw 从第三方来源获取 Skill;本站只展示命令,不托管安装包,也不自动执行。

ClawHubOpenClaw
openclaw skills install university-solution-explainer

简介

结构化拆解大学考试问题与计算步骤说明。

  • 聚焦学生视角提供可行解题路径建议。适用宿主包括 OpenClaw,接入前应确认版本、权限和运行环境要求。
  • 适用于数学、物理等理科科目疑难解答场景。
  • 答案推导过程需严格遵循教材公理体系。
  • university-solution-explainer 属于研究检索类 Skill,可作为该场景下的辅助能力补充。

SKILL.md

name
university-solution-explainer
description
|
author
eloklam

Solution Explainer

Break down questions and worked solutions with structured, student-friendly explanations.

Math Display

  • NO LaTeX syntax (may not render on all devices)
  • Use plain text for math: F = ma, s = F/c, x^2
  • Use subscripts naturally: F_B0, E_max
  • Use fractions with / : s = F/c, E = F × s / 2
  • Keep math readable without special formatting

Student-First Explanation Workflow

Think like a student solving the problem. Start from what the question asks, then work backwards to show WHY each step is needed. Assume you didn't know the answer — you work from what is being asked.

Step 1: Identify the Goal

Question asks: [What is being asked?]

Student thinks: [Basic formula for the answer]

Step 2: Gap Analysis

What do I have?
- [Given value 1] ✓
- [Given value 2] ✓
- [Unknown 1] ✗ ← Need to calculate!

So I need to find [Unknown 1]:
- [Formula for Unknown 1]
- [Check if all inputs available]

Step 3: Build the Dependency Chain

Work backwards from the goal, showing what depends on what:

Question asks for s → Need F → Need F_B0 → Got all values!

Step 4: Forward Calculation

Now calculate forward with the chain established:

Step 1: Calculate F_B0
Step 2: Calculate F
Step 3: Calculate s (answer)

Example: Spring Travel (Mechanics)

Question asks: s = ?

Student thinks: s = F/c

What do I have?

  • c_ges = 7.8 N/mm ✓ (calculated in part a)
  • F = ? ✗ ← Don't know!

So I need to find F:

  • F = F_B0 × cos(β) / 2
  • F_B0 = ? ✗ ← Need this first!

So I need to find F_B0:

  • F_B0 = m_ges × g × (a-b)/a
  • m_ges = 85 kg ✓
  • g = 10 m/s² ✓
  • a = 1300 mm ✓
  • b = 780 mm ✓
  • All values available!

Why divide by a?

Lever principle. Moment balance:

Moment = Force × Lever arm

Weight moment = Wheel force × Wheelbase
m × g × (a-b) = F_H0 × a

Dividing by a converts the moment back to a force.

Simple rule: (a-b)/a = lever arm ratio, determines how weight distributes to front/rear wheels.

Dependency chain:

Question asks for s → Need F → Need F_B0 → Got all values!

Calculation:

Step 1: Calculate F_B0 F_B0 = 85 × 10 × (1300-780)/1300 = 340 N

Step 2: Calculate F F = 340 × cos(20°) / 2 = 159.7 N

Step 3: Calculate s (answer) s = 159.7 / 7.8 = 20.57 mm


Structure Template

**Question: [Goal]**

Student thinks: [Basic formula]

What do I have?
- [Known quantity] ✓
- [Unknown quantity] ✗ ← Need to calculate!

So I need to find [Unknown]:
[Dependency chain]

**Dependency chain:**
Question asks for X → Need Y → Need Z → Got all values!

**Calculation:**
Step 1: ...
Step 2: ...
Step 3: (answer)

---

**Summary**

| Quantity | Value |
|---|---|
| ... | ... |

Formula Derivation Rule

⚠️ Important: Answer keys often skip steps

Formulas in the answer key are often simplified, with intermediate steps skipped. You must think through "why it becomes this" yourself, don't just copy directly.

Example 1: Dm = Di + d

Answer key writes Dm = Di + d directly, but actually:

        ┌─────────────────────┐
        │                     │  ← De (outer diameter)
        │   ┌─────────────┐   │
        │   │             │   │  ← Dm (mean diameter, wire center)
        │   │             │   │
        │   └─────────────┘   │
        │                     │  ← Di (inner diameter)
        └─────────────────────┘
             ↑    ↑    ↑
            Di   Dm   De

Dm = Di + 2 × (d/2) = Di + d

Why?

  • Di = inner diameter (inside of spring coil)
  • Dm = middle diameter (center of wire)
  • From inner edge to wire center = d/2
  • Both sides have this, so × 2

The answer key skipped the "2 × (d/2)" step — fill it back in yourself.


Example 2: (a-b)/a is the lever arm ratio

Answer key writes F_B0 = m × g × (a-b)/a directly, but actually:

Lever principle:
Moment = Force × Lever arm

Weight moment = Wheel force × Wheelbase
m × g × (a-b) = F_H0 × a

Divide by a → Convert moment back to force

The answer key skipped the moment balance explanation.


Principle:

See formula → Stop → Ask "why is this?" → Explain geometric/physical relationship → Then write it out

Tone

  • Think like a student, not a solution manual.
  • NEVER fight the answer provided in the PDF. They are from the professor and are always correct — work from them.
  • Assume you didn't know the answer. Work from what is being asked.
  • Show the "why" before the "how"
  • Explain formula derivations with geometric or physical reasoning
  • Use tables and structured blocks
  • Do not try to draw graphs unless asked
  • Ask if the user wants a deeper explanation on any part

适合场景

01

OpenClaw 用户查找和安装 Skill 时

02

用户想查找某类 Agent Skill 时

03

需要根据任务场景推荐可安装能力包时

04

需要对比不同来源的安装命令和来源信息时

能力概览

能力 1

按任务关键词查找相关 Skills

能力 2

展示可复制的安装命令

能力 3

保留来源站点、仓库和原始说明,方便继续核验

能力 4

补充不同宿主或平台的使用分布数据

能力 5

展示第三方安全扫描或审计结果

安装后应在对应宿主中按原始 README 的触发条件使用;具体调用方式请以来源页面和 README 为准。

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